arithmetic calendar questions and answers paper 355 - skillgunNote: Paper virtual numbers may be different from actual paper numbers . In the page numbers section website displaying virtual numbers .
The number of Sunday in a month if 25th of August in a year is Saturday ?
25th August is a Saturday.
So, 26th August is a Sunday.
So, Sunday fall on 26th, 19th, 12th, 5th
Thus, there are four Sundays.
Find out the number of days from 26th January, 1996 to 15th May, 1996(if both days are included)?
Number of days = (6 + 29 + 31 + 30 + 15 ) =111.
What is the day on 8th January 1901?
1st January 1901 means (1900 year and 1 day)
Now, 1600 years have 0 odd days
300 years have 1 odd day
1 day has 1 odd day
Total number of odd days = 0 + 1 + 1 = 2 days
Hence, The day of 1st January 1901 was Tuesday.
Therefore 8th January was also Tuesday.
X was born on March 6, 1993. The same year Independence Day was celebrated on Friday. On which day was X born?
Number of days from March 6, 1993 to August 15, 1993.
Mar Apr May June July August
= 25 + 30 + 31 + 30 + 31 + 15
= 162 days = 23 weeks + 1 day.
Clearly, the day on March 6 will be the same as on August 14, i.e., Thursday.
Find the day of the week on 25th December,1995?
Then 149 / 7 = 23 = 2 odd days.
Therefore the required day is Monday.
(Given: February 3, 1996 is Friday)
then find out the day on March 3, 1996 ?
1996 is a leap year and so February has 29 days.
Now, 1st, 8th, 15th, 22nd and 29th February are Wednesdays.
So, 1st March is Thursday and 3rd March is Saturday.
Monday was a holiday for Republic Day and 16th of the next month is again a holiday for Pongal. What day was it on the 16th?
None of these
As given, Monday falls on 26th January and we have to find the day on 14th February.
Clearly, 2nd, 9th and 16th February is Monday
Thus, 16th February was a Monday.
January 1, 1992 was a Wednesday, What day of the week will it be on January 1, 1993?
1992 being a leap year, it has 2 odd days.
So, the first day of the year 1993 will be two days beyond Wednesday
i.e., it will be Friday.
February 1, 1984 was a Wednesday just like the February 29, 1984. When will the calendar show another February with a similar situation?
The month of February 1984 had five Wednesdays. Only in a leap year this is possible. Seven leap years have to go by before this situation can occur again, because in each of the leap years the 29th would fall on a different weekday. Seven leap years means 7 x 4 = 28 years have to pass after 1984. Therefore it will be the year 2012 when a February again has five Wednesdays.
The year next to 1991 having the same calendar as that of 1991 is:
We go on counting the odd days from 1991 onward till the sum is divisible by 7.
The number of such days are 14 upto the year 2001.
So, the calendar for 1991 will be repeated in the year 2002.
On January 12, 1980, it was Saturday. The day of the week on January 12, 1979 was:
The year 1979 being an ordinary year, it has 1 odd day.
So, the day on 12th January 1980, is one day beyond the day on 12th January, 1979
But January 12, 1980 being Saturday
January 12, 1979 was Friday.
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