arithmetic - two stations p and q are 130 km apart one train starts from p at 930 am and travels towards q at 40 kmhr another train starts from q at 1030 am and travels towards p at a speed of 50 kmhr at what time will they meet - skillgun

suppose they meet x hours after 9.30 a.m.
distance covered by P in x hours = 40x km.
distance covered by Q in (x -1) hours = 50(x - 1) km.
.'. 40x + 50(x - 1) = 130 <=> 90x = 180 => x = 2 hours.
So, they meet at 11.30 a.m.