Anderson and Michael together can do a piece of work in 30 days.Anderson having worked for 16 days, Michael finishes the remaining work in 44 days. In how many days shall Michael finish the whole work alone?
Anderson's 1 day's work = x
Michael 's 1 day's work = y
Then, x+y = 1/30
and 16x+44y = 1
Solving these two equations, we get x = 1/10 and y=1/60
Therefore Michael 's 1 day's work= 1/60
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