arithmetic - it is being given that 316 1 is completely divisible by a whole number which of the following numbers is completely divisible by this number - skillgun

Let pow(3,16) = x. Then, pow(3,16) + 1 = (x + 1).
Let (x + 1) be completely divisible by the natural number N.
Then, pow(3,48) + 1) = [pow(pow(3,16),3)) + 1]
= (pow(x,3) + 1)
= (x + 1)(x2 - x + 1),
which is completely divisible by N, since (x + 1) is divisible by N.