The least multiple of 5, which leaves a remainder of 5, when divided by 8, 12, 20 is:

74

94

184

125

L.C.M. of 8, 12, 20 is 120. Let required number be 120k + 5, which is multiple of 5. Least value of k for which (120k + 5) is divisible by 5 is k = 1. Required number = (120 x 1) + 5 = 125.

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