arithmetic - three numbers which are coprime to each other are such that the product of the first two is 1102 and that of the last two is 2146 the sum of the three numbers is - skillgun

Since the numbers are co-prime, they contain only 1 as the common factor.
Also, the given two products have the middle number in common.
So, middle number = H.C.F. of 1102 and 2146 = 58;
First number = 1102/58 = 19
Third number = 2146/58 = 37
Required sum = (19 + 58 + 37) = 114