The least number which when divided by 3, 8 , 11 and 15 leaves a remainder 2, but when divided by 2 leaves no remainder, is:

677

1322

2523

3363

L.C.M. of 3,8,11,15 = 1320. Required number is of the form 1320k + 2 Least value of k for which (1320k + 2) is divisible by 2 is k = 1. Required number = (1320 x 1 + 2) = 1322.

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