arithmetic - let the least number of five digits which when divided by 5 6 13 and 15 leaves in each case the same remainder of 2 be p the sum of the digits in p is - skillgun

Least number of 5 digits is 10000.
L.C.M. of 5, 6, 13 and 15 = 390.
On dividing 10000 by 390, the remainder obtained is 250.
Least number of 5 digits divisible by 5, 6, 13 and 15 = 10000 + (390 – 250)
= 10140.
P = (10140 + 2) = 10142.
Sum of digits in P = (1 + 1 + +4 + 2) = 8