Find the least multiple of 5, which when divided by 18, 11 and 14 leaves remainders 7, 0 and 3 respectively.

272

301

605

36

Here (18 - 7) = 11, (11 - 0) = 11 and (14 - 3) = 11. L.C.M. of 18, 11 and 14 is 616. Let required number be 616k – 11. Least value of k for which (616k - 11) is divisible by 5 is k = 1 Required number = 616 x 1 - 11 = 616 - 11 = 605

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