Father is aged three times more than his son Koushik. After 8 years, he would be two and a half times of Koushik’s age. After further 8 years, how many times would he be of Koushik’s age?

2 times

2 1/2 times

2 3/4 times

3 times

Let Koushik’s present age be x years. Then, father’s present age = (x + 3x) years = 4x years. (4x + 8) = 5/2 (x + 8) 8x + 16 = 5x + 40 3x = 24 x = 8 Hence, required ratio = (4x + 16)/(x + 16) = 48/24 = 2

where 5/2 came from?

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