arithmetic - two years ago steven was 6 times as old as his son after 18 years he will be twice as old as his son their present ages in years are - skillgun

Let son's age 2 years ago be x.
Steven's age 2 years ago = 6x
2 (x + 2 + 18) = (6x + 2 + 18)
4x = 20
x = 5
Their present ages are (6x + 2) and (x + 2),
i.e., 32 years and 7 years.