arithmetic - the age of father 10 years ago was thrice the age of his son bujji ten years hence fathers age will be twice that of his son the ratio of their present ages is - skillgun

Let the ages of father and son 10 years ago be 3x and x years respectively
Then, (3x + 10) + 10 = 2 [(x + 10) + 10]
3x + 20 = 2x + 40
x = 20
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3