arithmetic - arun and varun appeared at an examination arun secured 9 marks more than varun and his marks was 56 of the sum of their marks what are the marks obtained by them - skillgun

Let the marks secured by them be x and (x + 9)
Then sum of their marks = x + (x + 9) = 2x + 9
Given that (x + 9) was 56% of the sum of their marks
=>(x+9)=56/100(2x+9)=>(x+9)=14/25(2x+9)
=> 25x + 225 = 28x + 126
=> 3x = 99
=> x = 33
Then (x + 9) = 33 + 9 = 42
Hence their marks are 42 and 33