Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

36

45

48

49

Relative speed = (60+ 90) km/hr = 150 x 5/18 m/sec = 125/3 m/sec. Distance covered = (1.10 + 0.9) km = 2 km = 2000 m. Required time = 2000 x 3/125 sec = 48 sec.

Back To Top