Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?
Let the cistern be filled by pipe A alone in x hours.
Then, pipe B will fill it in (x + 6) hours.
1/x + 1/(x + 6) = 1/4
(x + 6 + x)/ x(x + 6) = 1/ 4
x2 - 2x - 24 = 0
(x -6)(x + 4) = 0
x = 6. [ neglecting the negative value of x ]
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