A man covers a distance on scooter .If he had moved 3 kmph faster he would have taken 40 min less. If he had moved 2 kmph slower he would have taken 40 min more.The distance is:

20 meters

40 meters

50 meters

60 meters

Let distance = x m Usual rate = y kmph => x/y – x/y+3 = 40/60 hr => 2y(y+3) = 9x ————–1 => x/y-2 – x/y = 40/60 hr y(y-2) = 3x —————–2 Divide 1 & 2 equations by solving we get x = 40 mts

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