Two persons C & D started traveling from A and B which are 300 km apart, towards B and A
respectively at 1.00 p.m. C travels at a constant speed of 30 kmph whereas D doubles his speed every
hour. If D reaches A in 4 5/8 hours, at what time did C and D meet each other?
Let speed of D in first hour = x
D’s speed = x+ 2x+ 4x+ 8x+ 16x*(5/8) = 25x
Given 25 x=300 :. x = 12
At the end of four hours C traveled (30 *4) = 120 kmph
and D traveled 12 + 24+ 48 +96 = 180 kmph
They meet each other after 4 hours i.e at 5: p.m.
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