Starting with 1984, we go on counting the number of odd days till sum is divisible by 7.
Year 1985 1986 1987 1988 1989
Odd days 2 1 1 1 2 = 7 odd days = 1 week
=>0 odd day.
Calendar for 1984 will be the same as that of 1989.

We need to have 0 odd days, counting from 1982,
Therefore 1988 could be the year with the same calendar as 1982, buts itâ€™s a leap year and 1982 is not. Therefore next is 1993, where it fits, so calendar of 1982 is same as 1993