Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 minutes. In how much time, the third pipe alone can empty the cistern?
Work done by the third pipe in 1 min. = 1/50 - (1/60+1/75)
= (1/50 - 3/100)
Therefore, the third pipe alone can empty the cistern in 100 min.
Back To Top