infosys - a woman cycling a bicycle with speed p for a distance a km after completing 12 of her journey she slows down to 12 of his initial speed and completes her cycling half an hour late than planned time what will be the ratio of the distance to the speed - skillgun

Here Assume the distance be A and the speed initially be P.
Using same logic as we used for previous two questions, we get,
A/2P + [A-(A/2)]/(P/2) = A/P + 1/2
A/2P + [4A-2A]/2P = A/P + 1/2
A/2P = 1/2
A = P or A/P = 1
Thus 1:1 is the required ratio.