A Woman cycling a bicycle with speed P for a distance A km. After completing 1/2 of her journey she slows down to 1/2 of his initial speed and completes her cycling half an hour late than planned time. What will be the ratio of the distance to the speed?
Here Assume the distance be A and the speed initially be P.
Using same logic as we used for previous two questions, we get,
A/2P + [A-(A/2)]/(P/2) = A/P + 1/2
A/2P + [4A-2A]/2P = A/P + 1/2
A/2P = 1/2
A = P or A/P = 1
Thus 1:1 is the required ratio.
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