If the digit in the ten's place of a two digit number is 3 less than the digit unit’s place and if the ratio of the sum of the digits of that number to that of the number is 1:4 then the number is:
Assume the ten’s digit of the number be x.
Then the unit’s digit is x+3
Sum of the digits = x + x + 3 = 2x+3.
Then the number can be expressed as 10x +(x+3) = 11x + 3
The given ratio between the sum of digits to the sum = 1 / 4 = 2x+3 / 11x+3
4(2x + 3) = 11x + 3
3x = 9
x = 3
Then the required number is 11x + 3 = 11(3) + 3 = 36.
Hence the answer is 36.
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