mphasis - a can p contains sugar with 40 water and can q contains sugar with 70 water another can r contains 20 parts from p and 8 parts from q the of water in the can r is - skillgun

Number of parts in can R = 20 +8 = 28 parts.
20 parts of R = sugar with 40% water.
8 parts of R = sugar with 70% of water.
Therefore total quantity of water = 40% of 20 + 70% of 8 = 8 + 28/5
Percentage of water in the can C = (Total Quantity of water / Number of parts in C) x 100 %
= {(8 + 28/5) / 28} x 100 % = 68 x 100 / 5 x 28 = 48.5%