805 ml of mixture1 is mixed with 700ml of mixture2. If mixture1 has acid1 and acid2 in the ratio 4:3 and mixture2 has acid2 and acid3 in the ratio 2:5 then the amount of acid2 in the new mixture is:
acid1 and acid2 is in the ratio 4:3, then
Quantity of acid2 in 805ml of mixture1 = 805 x 3 / 7 = 345 ml
And acid2 and acid3 in the ratio 2:5.
Quantity of acid2 in 700ml of mixture2 = 700 x 2 / 7 = 100 x 2 = 200ml
Therefore quantity of acid2 in new mixture = 345 + 200 = 545ml.
Hence the required answer is 545 ml.
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