The two digit number which is there in set that is selected at random so that, we have to find the probability that the selected number will be a multiple of '8'.
There are a total of 90 two digit numbers.
So,the set contains 90 numbers.
We know that the first two digit number that is a multiple of 8 is 16 and every 8th number from 17 will be a multiple of 8. there are 11 (integral value of 90/8 = 11) of those numbers that are divisible by '8'.(alternatively the two digit multiples of 8 are 16,24,32,40,48,56,64,72,80,88 and 96)
Then, the required probability is 8/90 = 4/45
Back To Top