arithmetic - 8 years ago the average age of a family of 5 members was 26 years two children having been bornwith age difference of 2 years the present average age of the family is the same the present age of the eldest child is - skillgun

Solution: Total age of 5 members, 8 years ago = (26*5)years = 130 years.
Total age of 5 members now = (130+ 8*5) years = 170 years.
Total age of 7 members now = (26*7) years = 182 years.
Sum of the ages of 2 children = (182 - 170) years = 12 years.
Let the age of the younger child be x years.
Then, age of the elder child = (x + 2)years.
So, x + x+ 2 = 12
=> 2x = 10
=> x = 5.
.'. Age of the elder child is = 5 + 2 = 7 years.