In a college A Mathematics lecturer asked a Question to students that "A square of a number is divided into two unequal parts such that 4 times the difference of them is equal to the difference of their individual squares". find the number ?
Assume the number be x
Then the square of the number = x2. Assume the two unequal parts be a and b.
Then a + b = x2
4 times the difference of them = 4(a - b)
And the difference of their individual squares = a2 - b2.
4(a - b) = a2 - b2.
4(a - b) = (a - b)(a + b)
4 = (a + b)
16 = x2 (by a + b = x2)
x = 2
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