arithmetic - madhav and raghava can do a work in 16 days raghava and ravi can do the same work in 24 days madhav raghava and ravi together can finish it in 12 days madhav and ravi together will do it in - skillgun

Solution: Let A = Madhav, B = Raghava, C = Ravi.
(A+B+C)'s 1 day's work = 1/12; (A+B)'s 1 day's work = 1/16;
(B+C)'s 1 day's work = 1/24.
.'. (A+C)'s 1 day's work = 2(A+B+C) - [(A+B)+(B+C)]
= 2*1/12 - (1/16 + 1/24)
= 2/12 - 10/96 = (16-10)/96 = 6/96 = 1/16.
So, Madhav and Ravi together will do the work in 16 days.