arithmetic - four men three women and six children can complete a work in 14 days a man does double the work a woman does and a child does half the work a woman does how many children alone can complete this work in 28 days - skillgun

Solution: Let 1 man's 1 day's work = x.
Then, 1 woman's 1 day's work = x/2 and 1 child's 1 day's work = x/4.
so, (4x + 3x/2 + 6x/4) = 1/14
=> 28x/4 = 1/14
=> x = (1/14 * 4/28) = 1/98.
.'. 1 man alone can complete the work in 98 days.
so, 1 child alone can complete the work in 98*4 = 392 days.
so, to complete the work in 28 days, number of children required = 392/28 = 14 days.