Two taps fill in tank in 20 hours. and 10 hours. Two taps are opened first. After how much time the second tap should be closed off so that the tap full in 14 hours ?
Solution: Let the second pipe closed off after x hours.
Then, 14*1/20 + x*1/10 = 1.
14 + 2x = 20
=> 2x = 6
=> x = 3.
.'. Second pipe should be closed off after 3 hours.
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