Narayana's age was equal to square of a number last year and the following year it would be cube of a number ,If again Narayana's age has to be equal to the cube of some number ,then for how long he will have to wait?
Clearly, we have to first find two numbers whose difference is 2 and of which the smaller one is a perfect square and the bigger one a perfect cube.
Such numbers are 25 and 27.
Thus,Narayana is now 26 years old. Since the next perfect cube after 27 is 64,
so required time period = (64 - 26) years = 38 years.
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