One day, a boy from his house walks at a speed of 5 km/hr and reaches his school 2 minutes late. Next day he increases his speed by 1 km/hr and reaches the school 2 minutes early. How far is the school from his house ?
Solution: Let the distance be x km.
Difference in timings = 4 min = 4/60 hr
= 1/15 hr.
.'. x/5 - x/6 = 1/15
=> 6x-5x = 30/15
=> x = 2 km.
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