One day, a boy from his house walks at a speed of 5 km/hr and reaches his school 2 minutes late. Next day he increases his speed by 1 km/hr and reaches the school 2 minutes early. How far is the school from his house ?

2 km.

3 km

4 km

5 km

Solution: Let the distance be x km. Difference in timings = 4 min = 4/60 hr = 1/15 hr. .'. x/5 - x/6 = 1/15 => 6x-5x = 30/15 => x = 2 km.

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