A man driving a car was travelling with some constant speed and covered a certain distance. If the speed of the car was increased by 3 kmph, then the journey time was reduced by 40 minutes. If the speed of the car had been reduced 2 kmph slower, then he would have taken 40 minutes more. Find the distance covered (in km) by the car?
Solution: Let distance = x km and usual rate = y kmph.
Then, x/y - x/(y+3) = 40/60 or 2y(y + 3) = 9x ....... (i)
And, x/(y-2) - x/y = 40/60 y(y - 2) = 3x ........(ii)
On dividing (i) by (ii), we get: x = 40.
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