A boy goes to a playground from the house at 5 km/hr by 10 minute late. If he goes at 6 km/hr. he would be 5 minutes early. What is the distance of the of playground from his house ?
Solution: Let the distance be x km.
Difference in timings = 15 min = 15/60 hr = 1/4 hr.
.'. x/5 - x/6 = 1/4
=> 6x-5x = 30/4
=> x = 7.5 km.
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