arithmetic - a thief steals a car at 405 pm and drives it at 55 kmhr the theft is discovered at 420 pm and the owner sets off in another car at 70 kmhr when will he overtake the thief - skillgun

Solution: Suppose the thief is overtaken x hrs after 4.05 P.M.
Then, distance covered by the thief in x hrs. = distance covered by owner in (x - 1/4) hrs.
.'. 55x = 70(x - 1/4)
=> 15x = 70/4
=> x = 70/(15*4) hr = 14/12 hr
=> x = (14/12 * 60) min = 70 min.
So, the thief is overtaken at 5.15 pm.