A train A leaves Mysore at 6 a.m. and reaches Bangalore at 10 a.m. Another train leaves B Bangalore at 8 a.m. and reaches Mysore at 11.30 a.m. At what time do the two trains cross each other ?
Solution: Let the distance between mysore and bangalore be x km and let the trains meet y hours after 8 a.m.
Clearly, A covers x km in 4 hours and B covers x km in 4.5 hrs = (7/2) hrs
.'. Speed of A = x/4 kmph, speed of B = 2x/7 kmph.
Distance covered by A in (y+2) hrs + distance covered by B in y hrs = x.
.'. x/4(y+2) + 2x/7 * y = x
=> (y+2)/4 + 2y/7 = 1
=> y = 14/15 hrs =14*60/15 = 56 min.
Hence, the trains meet at 8.56 a.m.
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